Question

(x^2-7)^2-4(x^2-7)-45=0 решите уравнение

Answer 1

$x^2-7=t\t^2-4t-45=0\t_1=9 t_2=-5\x^2-7=9 x^2-7=-5\x^2=16 x^2=2\x=pm4 x=pmsqrt{2}$

Ответ: $x=pm4,x=pmsqrt{2}$