Question

5x+3y=1 2x+6y=0 система урав.неравенств

Answer 1

$left { {{5x+3y=1} | *(-2) atop {2x+6y=0} right. \ \ left { {{-10x-6y=-2} atop {2x+6y=0} right. \ \ -10x+2x-6y+6y=-2+0\ -8x=-2\ 8x=2\ x=frac{2}{8}\ \ x=frac{1}{4}\ \ 2*frac{1}{4}+6y=0\ 6y=-frac{1}{2}\ \ y=-frac{1}{2}*frac{1}{6}\ \ y=-frac{1}{12}$

Ответ: х=1/4,  у=-1/12

Answer 2

5x+3y=1

2x+6y=0

 

2х=-6y

х=-3y

 

5*(-3y)+3y=1

-15y+3y=1

-12y=1

y=-1/12

 

х=-3*(-1/12)

х=1/4