Question

решите систему x - y = 2 и 2 x - y в квадрате = 5

Answer 1

x-y =2
2x-y² = 5

x = 2+y
2(2+y) - y² = 5

x = 2+y
-y² + 2y + 4 - 5 = 0

y² - 2y +1 =0
D = 2² -4 = 0
y = 2/2 = 1

x = 2 + 1 = 3
y = 1