Question

СРОЧНО!!! Не знаю решение, но ответ будет [3,4).

Answer 1

$left { {{(x-3)(x-1) geq 0} atop {x>2}} right. ; |x|<4\\ left { {{xin (-infty ,1]U[3,+infty)} atop {xin (2,+infty)}} right. ; to ; ; \\++++[1]----(2)----[3]+++++++\\xin [3,+infty)\\|x|<4; ; to ; ; -4<x<4$

$left { {{x geq 3} atop {x<4}} right. to xin [3,4)$