Question

ПОМОГИТЕ решить систему!!!
отдаю последние баллы!

Answer 1

$left { {{4x-3y=1} atop {8*2x=6*(9-5y)}} right. \ \ left { {{4x=1+3y} atop {16x=54-30y}} right. \ \ left { {{x=frac{1+3y}{4}} atop {16x=54-30y}} right. \ \ 16*(frac{1+3y}{4})=54-30y \ 4*(1+3y)=54-30y \ 4+12y=54-30y \ 12y+30y=54-4 \ 42y=50 \ y=frac{50}{42}=frac{25}{21} \ \ x=frac{1+3*frac{25}{21}}{4}=frac{1+frac{25}{7}}{4}=frac{frac{7}{7}+frac{25}{7}}{4}=frac{frac{32}{7}}{4}= frac{32}{7} * frac{1}{4} = frac{8}{7}$

Answer 2

х=(1+3у)/4
2*((1+3у)/4)/6=(9-5у)/8
________
х=(1+3у)/4
((1+3у)/12) - ((9-5у)/8) = 0
________
х=(1+3у)/4
(2+6у-27+15у)/24 = 0
_______
х=(1+3у)/4
21у-25=0
______
х=(1+3у)/4
у=25/21
_______
х=(1+3*25/21)/4
у=25/21
_______
х=8/7
у=25/21

сам целые числа сделаешь