Question

(3xy-1/3x^2y^2)^3 помогите

Answer 1

1)y=3/(2x-1)⇒x=3/(2y-1)⇒2y-1=3/x⇒2y=3/x + 1=(3+x)/x⇒y=(x+3)/2x
2)y=x²-4⇒x=y²-4⇒y²=x+4⇒y=
4)y=⇒x=⇒x²=25-y²⇒y=