Question

9^x +3^(2x+1) = 4^(x+1)

Answer 1

9^[x] + 3^[2x+1] = 4^[x+1]

1+3-4*(4/9)^[x] = 0

4-4*(4/9)^[x] = 0

-4*(4/9)^[x] = -4

(4/9)^[x] = 1

(4/9)^[x] = (4/9)^[0]

x=0

Ответ: 0.

Answer 2

3^[2x]+3*3^[2x]=4^[x+1]
4*3^[2x]=4^[x+1]
Потом дальше делим

Answer 3

благодарюю!!))))