Question

Решите неравенства:
А) log1/2(2x+1)>-2
Б)(1/4)^х'2-6<(1/2)^10х

Answer 1

А) log1/2(2x+1)>-2
(1/2)^ (-2) = 2x + 1
2x = 3
x = 3/2
x = 1,5

Б)   (1/4)^х'2-6<(1/2)^10х
(1)2)^(2x^2 - 12) < (1/2)^(10x)Так как   o< 1/2  < 1, то
2x^2 - 12 > 10x
2x^2 - 10x - 12 > 0
x^2 - 5x - 6 > 0
x1 = - 1
x2 = 6
x∈( -≈; -1)  (6; +≈)