Question

Помогите вычислить:
А) (3/7)^-1
Б) 16^1/4-125^1/3
Г) (2+3^2/3)(4-2*3^2/3+3^4/3)

Answer 1

(3/7)^-1 = 7/3

16^1/4 - 125^1/3 = 2^{4*1/4} - 5^{3*1/3} = 2-5=-3

(2+3^{2/3})(4-2*3^{2/3}+3^{4/3})=2^3 +9 = 8+9 = 17