Question

a^{2} - 9a + 20
b^{2} +3b+2
c^{2} -5c+6
d^{2} -7d-8
Решите срочно !!!!!!!!!!!!!
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Answer 1

$a^2-9a+20=a^2-4a-5a+20=a(a-4)-5(a-4)= \ =(a-5)(a-4) \ \ b^2+3b+2=b^2+b+2b+2=b(b+1)+2(b+1)=(b+1)(b+2) \ \ \ c^2-5c+6=c^2-3c-2c+6=c(c-3)-2(c-3)= \ =(c-2)(c-3) \ \ d^2-7d-8=d^2+d-8d-8=d(d+1)-8(d+1)=(d+1)(d-8)$