Ответы
Ответ дал:
0
а)
![a^2-2ab+b^2=(a-b)^2 a^2-2ab+b^2=(a-b)^2](https://tex.z-dn.net/?f=a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2)
в)
![9m^2-6m+1=(3m)^2-2*3m*1+1^2=(3m-1) 9m^2-6m+1=(3m)^2-2*3m*1+1^2=(3m-1)](https://tex.z-dn.net/?f=9m%5E2-6m%2B1%3D%283m%29%5E2-2%2A3m%2A1%2B1%5E2%3D%283m-1%29)
д)
![16p^2-56pq+49q^2=(4p)^2-2*4p*7q+(7q)^2=(4p-7q)^2 16p^2-56pq+49q^2=(4p)^2-2*4p*7q+(7q)^2=(4p-7q)^2](https://tex.z-dn.net/?f=16p%5E2-56pq%2B49q%5E2%3D%284p%29%5E2-2%2A4p%2A7q%2B%287q%29%5E2%3D%284p-7q%29%5E2)
ж)
![x^4-6x^2y+9y^2=(x^2)^2-2*3y*x^2+(3y)^2=(x^2-3y)^2 x^4-6x^2y+9y^2=(x^2)^2-2*3y*x^2+(3y)^2=(x^2-3y)^2](https://tex.z-dn.net/?f=x%5E4-6x%5E2y%2B9y%5E2%3D%28x%5E2%29%5E2-2%2A3y%2Ax%5E2%2B%283y%29%5E2%3D%28x%5E2-3y%29%5E2)
в)
д)
ж)
Вас заинтересует
1 год назад
6 лет назад
9 лет назад