Question

Вычислить:
$3^{4log_{3}2 } + log_{5} sqrt{2} * log_{4} 25 =$

Answer 1

$3^{4log_32}+log_5sqrt{2}*log_45^2=(3^{log_32})^4+log_5sqrt{2}*frac{2}{log_54}=\=2^4+2frac{log_52^frac{1}{2}}{log_52^2}=16+2*frac{frac{1}{2}log_52}{2log_52}=16+frac{1}{2}=16.5$