Question

log2(8x-2)=2


log2(x+2)+log2(2x-3)=2

Answer 1

1)log2(8x-2)=2 
8x-2=2²
8x-2=4
x=3/4
2)
log2(x+2)+log2(2x-3)=2
(x+2)(2x-3)=4
2x²-3x+4x-6=4
2x²+x-10
d=9
x1/x2 = (-1+-9)/4= 2,-2.5 -посторонний корень  
х=2