Question

log1/2(x+7)>-3 помогите пжлст

Answer 1

$log_{ frac{1}{3}}(x+7)>-3cdot 1$
$1=log_{ frac{1}{3}} frac{1}{3}$
$log_{ frac{1}{3}}(x+7)>-3cdot log_{ frac{1}{3}} frac{1}{3} \ log_{ frac{1}{3}}(x+7)> log_{ frac{1}{3}} (frac{1}{3}) ^{-3} \ log_{ frac{1}{3}}(x+7)> log_{ frac{1}{3}}27Rightarrow left { {{x+7>0} atop {x+7<27}} right.$
$left { {{x>-7} atop {x<20}} right.$
Ответ. (-7; 20)