Question

Помогите пожалуйста
1)6x^{2}+13x+4=0
2) 5x^{2}+24x+9=0
3) 7x^{2}-27x+12=0
4) 4x^{2}+3x-2=0
5)6x^{2}-10x-1=0

Answer 1

$6x^2+13x+4=0 \ delta=13^2-(6*4*4)=169-96=73 \ x_1= frac{-b- sqrt{delta} }{2a} = frac{-13- sqrt{73} }{12} \ x_2= frac{-b+ sqrt{delta} }{2a} = frac{-13+ sqrt{73} }{12}$

$5x^2+24x+9=0 \ delta=24^2-(9*5*4)=576-180=396 \ x_1= frac{-b- sqrt{delta} }{2a} = frac{-24- sqrt{396} }{10} \ x_2= frac{-b sqrt{delta} }{2a} = frac{-24+ sqrt{396} }{10}$

$7x^2-27x+12=0 \ delta=(-27)^2-(7*12*4)=393 \ x_1= frac{27- sqrt{393} }{14} \ x_2= frac{27+ sqrt{393} }{14}$

$4x^2+3x-2=0 \ delta=3^2-(-2*4*4)=9-(-32)=9+32=41 \ x_1= frac{-3- sqrt{41} }{8} \ x_2= frac{-3+ sqrt{41}}{8 }$

$6x^2-10x-1=0 \ delta=(-10)^2-(-1*6*4)=100+24=124 \ x_1= frac{10- sqrt{124} }{12} \ x_2= frac{10+ sqrt{124} }{12}$

Answer 2

Can you solve this

Answer 3

Steel parts weighing 20kg with a lathe warmed to 50 degrees. How much heat to get the item?

Answer 4

But I have already resolved it.

Answer 5

Well I Do not Know help

Answer 6

???