Question

log2(4x+1)=log2(3x+7)

Answer 1

Log2(4x+1)=log2(3x+7)
Система:
4x+1=3x+7
4x+1>0
4x-3x=7-1
x=6
4*(6)+1>0
24+1>0 
Ответ: 6

Answer 2

спасиб

Answer 3

а log2(4x+1)=(3x+7)

Answer 4

ой

Answer 5

log2(x^2 -x)=1

Answer 6

log2(x^2 -x)=1