Question

помогитеее)))пожалуйста)))

Answer 1

1)
а)
$sqrt{121}=sqrt{11^2}=11$
$sqrt{1.44}=sqrt{1.2^2}=1.2\sqrt{frac{16}{225}}=sqrt{frac{4^2}{15^2}}=frac{4}{15}\sqrt{1frac{25}{144}}=sqrt{frac{169}{144}}=sqrt{frac{13^2}{12^2}}=frac{13}{12}$


б)
$(sqrt{3})^2=3\(-sqrt{13})^2=(-1)^2*(sqrt{13})^2=1*13=13\(sqrt{5})^4=5^2=25$


в)
$(3sqrt{5})^2=3^2*5=9*5=45\-3*sqrt{(-5)^2}=-3*sqrt{5^2}=-3*5=-15\(-3sqrt{5})^4=(-3)^4*(5)^2=81*25=2025$


г)
$sqrt{729}-sqrt{529}=sqrt{27^2}-sqrt{23^2}=27-23=4\sqrt{frac{1}{9}}*sqrt{0.36}=sqrt{frac{1^2}{3^2}}*sqrt{0.6^2}=frac{1}{3}*0.6=0.2$



2)
a)
$x^2=121\sqrt{x^2}=sqrt{121}\|x|=11\x=11 x=-11$

б)
$x^2=11\sqrt{x^2}=sqrt{11}\|x|=sqrt{11}\x=sqrt{11} x=-sqrt{11}$

в)
$sqrt{x}=11\(sqrt{x})^2=11^2\x=121$