Question

sinx=√3÷2
tg (x -pi÷10)=1

Answer 1

sinx=√3÷2
x=(-1)^n*π/3+πn, n∈Z

tg(x-π/10)=1
x-π/10=π/4+πn, n∈Z
x=π/4+π/10+πn, n∈Z
x=7/20 π+πn, n∈Z