Question

Помогите, срочно надо!

Answer 1

(2^x)*3^(y + 1) = 72
log(2)  (x - y) = 1

(2^x)*3^(y + 1) = 72
x - y = 2

y = x - 2
(2^x)*3^(x - 2 + 1) = 72

(2^x)*3^(x - 1) = 72
(2^x)*(3^x)*(1/3) = 72
(6^x) = 72*3
(6^x) = 216
(6^x) = (6)^3
x = 3
 y = 3 - 2 = 1

Ответ: (3;1)