Question

4cos(квадрат)x-3=0 пожалуйста

Answer 1

4cos^2x = 3
cos^2x = 3/4
1)  cosx = √3/2
x = (+ -)arccos(√3/2) + 2πn, n∈Z
x = (+ -)(π/6) + 2πn, n∈Z
2)  cosx = - √3/2
x = (+ -)arccos(-√3/2) + 2πn, n∈Z
x = (+ -) (π - π/6) + 2πn, n∈Z
x = (+ -)(5π/6) + 2πn, n∈Z