Question

РЕШИТЕ ПОЖАЛУЙСТА СРОЧНО НАДО !!!!

Answer 1

$= lim_{x to 3} frac{(x^2-9)(sqrt{4x-3}+3)}{ (sqrt{4x-3}-3)(sqrt{4x-3}+3) } = lim_{x to 3} frac{(x^2-9)(sqrt{4x-3}+3)}{4x-3-9} =\= lim_{x to 3} frac{(x-3)(x+3)(sqrt{4x-3}+3)}{4(x-3)}= lim_{x to 3} frac{(x+3)(sqrt{4x-3}+3)}{4}=\=frac{(3+3)(sqrt{12-3}+3)}{4}= frac{6*6}{4} =9$