Question

log2(2 − 5х) = log2(1 − 5х) + 1

Answer 1

Log2(2 − 5х) = log2(1 − 5х) + 1=log2(2-5x)-log2(1-5x)=1
log2(2-5x)/(1-5x)=1
(2-5x)/(1-5x)=2
2(1-5x)=2-5x
2-10x=2-5x
-10x+5x=2-2
-5x=0
x=0