Question

2sin^2(x)=cos(3п/2-x)

Answer 1

2sin^2x - sinx = 0
sinx(2sinx - 1) = 0
1)  sinx = 0
x1 = πn, n∈Z
2)  2sinx - 1 = 0
sinx = 1/2
x = (-1)^n*arcsin(1/2) + πk, k∈Z
x = (-1)^n*(π/6) + πk, k∈Z