Question

(x-1)(x²+6x+9)=5(x+3) решите пж

Answer 1

$(x-1)(x^2+6x+9)=5(x+3)\(x-1)(x+3)^2-5(x+3)=0\(x+3)((x-1)(x+3)-5)=0\\x+3=0\boxed{x=-3}\\(x-1)(x+3)-5=0\x^2+3x-x-3-5=0\x^2+2x-8=0\D=4+32=36=6^2\boxed{x_1=frac{-2+6}{2}=2}\boxed{x_2=frac{-2-6}{2}=-4}$

Ответ: x=-3, x=-4, x=2