Question

найти производную функции (x^3-2x^2+5)^6

Answer 1

((x^3-2x^2+5)^6)'=6*(x^3-2x^2+5)^5*(3x^2-4x)

Answer 2

$((x^3-2x^2+5)^6)'=6(x^3-2x^2+5)^{6-1}(x^3-2x^2+5)'=\ 6(x^3-2x^2+5)^{5}((x^3)'-(2x^2)'+(5)')=6(x^3-2x^2+5)^{5}(3x^2-2(x^2)'+0)=\ 6(x^3-2x^2+5)^{5}(3x^2-2*2x)=\6(x^3-2x^2+5)^{5}(3x^2-4x)$