Question

решите уравнение -3(3y+4(2у-1)=0

Answer 1

-3(3у + 4(2у - 1)) = 0    или     -3(3у + 4(2у - 1)) = 0 
-3(3у + 8у - 4) = 0                     3у + 4(2у - 1) = 0 
-3(11у - 4) = 0                           3у + 8у - 4 = 0
-33у + 12 = 0                            11у = 4
-33у = -12                                 у = 4/11
у = 12/33
у = 4/11