Question

Решите уравнение
(x+2)^2=(x-4)^2

Answer 1

$(x+2)^2=(x-4)^2 \ x^2+4x+4=x^2-8x+16 \ 12x=12 \ x=1$

Answer 2

$(x+2) ^{2} =(x-4) ^{2} \ x^{2} +4+4x= x^{2} +16-8x\ x^{2} +4x- x^{2} +8x=16-4\4x+8x=12\12x=12\x=12/12\x=1$