Question

2sin(2x-п/4)=-√2помогите пожалуйста

Answer 1

2sin(2x-π/4)=-√2
sin(2x-π/4)=-√2/2
2x-π/4=(-1)^{n+1}*π/4+πn, n∈Z
2x=(-1)^{n+1}*π/4+π/4+πn, n∈Z
x=(-1)^{n+1}*π/8+π/8+πn/2, n∈Z