Question

Помогите решить уравнение: 27^1+2x=(1/9)^2+x

Answer 1

27^(1+2x)=(1/9)^(2+x)
(3^3)(1 + 2x) = (3^-2)(2+x)
3^(3+ 6x) = 3^(-4 - 2x)
3 + 6x = -4 -2x
8x = -4 - 3
8x = -7
x = -7/8

Answer 2

27^(1+2х)=1/9^(2+х), 3^(3*(1+2х) )=3^(-2*(2+х) ), 3*(1+2х)=-2*(2+х) 3+6х=-4-2х, 6х+2х=-4-3 8х=-7, х=-7 : 8, х= -7/8