Question

x^2-4x+35=-9x^2+11x+45

Answer 1

$\ x^{2} -4x+35=-9 x^{2} +11x+45 \ \ x^{2} +9 x^{2} -4x-11x+35-45=0 \ \ 10 x^{2} -15x-10=0 \ \ 10*( x^{2} -1.5x-1)=0 \ \ x^{2} -1.5x-1 = 0 \ \ \ D= (-1.5)^{2} -4*(-1)=2.25+4=6.25 \ \ sqrt{6.25} = 2.5 \ \ x_{1} = frac{1.5-2.5}{2} =-0.5 \ \ x_{2} = frac{1.5+2.5}{2} =2$
Ответ: х1=-0,5
           х2=2