Question

решите
$sqrt{2 x^{2} -3x+2} =4-x$

Answer 1

$sqrt{2 x^{2} -3x+2} =4-x \ \ 2 x^{2} -3x+2= x^{2} -8x+16 \ \ x^{2} +5x-14=0 \ \ (x+7)(x-2)=0 \ \ x=-7 \ \ x=2$