Question

(2x-1)^2=3x^^2-4x+17

Answer 1

$(2x-1)^{2}=3x^{2}-4x+17 \ 4x^{2}-4x+1=3x^{2}-4x+17 \ 4x^{2}-4x+1-3x^{2}+4x-17=0 \ x^{2}-16=0\ x^{2}=16 \ x=4; x=-4;$

Ответ: ±4.