Question

реште уровнение
1)(х+4)^2-(х-2)(х+2)=0
2)(3х+5)(3х-5)-(3х-1)^2=10

Answer 1

(x+4)²-(x-2)(x+2)=0
x²+8x+16-(x²-4)=0
x²+8x+16-x²+4=0
8x+20=0
8x=-20
x=-20/8
x=-2,5

(3x+5)(3x-5)-(3x-1)²=10
9x²-25-(9x²-6x+1)=10
9x²-25-9x²+6x-1=10
6x-26=10
6x=36
x=36/6
x=6