Question

Помогите с алгеброй!

Answer 1

ОДЗ
$xneq 0$

$dfrac{1}{x^2} - dfrac{3}{x}-4=0\\\ dfrac{1-3x-4x^2}{x^2} =0\\\1-3x-4x^2=0\4x^2+3x-1=0\D=25\\x_1=dfrac{-3+5}{8}= dfrac{1}{4} ;quad x_2=-1$