Question

Помогите решить уравнение!!!

x^3 - 6x^2 + 32 = 0

Answer 1

x^3+6x^2-32=0 
x^3-2x^2+8x^2-32=0 
x^2(x-2)+8(x^2-4)=0
x^2(x-2)+8(x-2)(x+2)=0
(x-2) (x^2 +8(x+2))=0
(x-2) (x^2 +8x +16)=0
(x-2) (x^2 +2*4*x +4^2)=0
(x-2) (x+4)^2 = 0