Question

Помогите пожалуйста, алгебра 7 класс 40 баллов даю
рушите 15 номер, с пункта Е и до конца

Answer 1

$2(x-4)+c(4-x)-a(x-4)=2(x-4)-c(x-4)-a(x-4)= \ =(x-4)(2-c-a) \ 2(a+b-c)+x(a+b-c)-y(a+b-c)=(a+b-c)(2+x-y) \ (x+2z)(x-3y)+(x+2z)^{2} =(x+2z)(x-3y+x+2z)= \ =(x+2z)(2x-3y+2z) \ (a-x)(a+x^{2} ) + (x-a)x^{2}=(a-x)(a+x^{2} ) - (a-x)x^{2}= \ =(a-x)(a+x^{2}-x^{2})=(a-x)a \ a( a^{2} +2ab)- a^{3} = a( a^{2} +2ab)- a*a^{2} = a*(a^{2} +2ab -a^{2})= \ =a*2ab=2a^{2}b \ c^{3} (d-4)^{3}+ c^{2} (d-4)^{4}=c^{2}(d-4)^{3}(c+d-4)$

$a^{5} (b-c)^{7}+ a^{6} (c-b)^{5}= a^{5}(b-c)^{7}- a^{6} (b-c)^{5}= \ =a^{5}(b-c)^{5}((b-c)^{2} - a) = a^{5}(b-c)^{5}(b^{2}-2bc+c^{2}- a)$