• Предмет: Математика
  • Автор: abaytan
  • Вопрос задан 8 лет назад

15 целых 8/41 найдите разность
5 3/7 -4
9 8 /17-5
8-5/19
9-5 1/12
6-8/9
4 3/8-1/5
6 1/2-2/5
9 5/6-1/3
5 1/3- 2/9
8 17/21-2/3
3 5/7-5/6
1 2/3-1/8
буду благодарна заранее спасибо

Ответы

Ответ дал: VasiaZozulia
0
15 - 8/41 = 14 41/41 - 8/41 = 14 33/41
5 3/7 - 4 = 5 3/7 - 3 7/7 = 1 3/7
9 8 /17-5 = 9 8/17 - 4 17/17 = 4 8/17
8-5/19 = 7 19/19 - 5/19 = 7 14/19
9-5 1/12 = 8 12/12 - 5 1/12 = 3 11/12
6-8/9 = 5 9/9 - 8/9 = 5 1/9
4 3/8-1/5 = 35/8 - 1/5 = (35*5 - 1*8)/40 = 167/40 = 4 7/40
6 1/2-2/5 = 13/2 - 2/5 = (13*5 - 2*2)/10 = 61/10 = 6 1/10
9 5/6-1/3 = 59/6 - 1/3 = (59 - 1*2)/6 = 57/6 = 9 1/2
5 1/3- 2/9 = 16/3 - 2/9 = (16*3 - 2)/9 = 46/9 = 5 1/9
8 17/21-2/3 = 185/21 - 2/3 = (185 - 2*7)/21 = 171/21 = 8 1/7
3 5/7-5/6 = 26/7 - 5/6 = (26*6 - 5*7)/42 = 121/42 = 2 37/42
1 2/3-1/8 = 5/3 - 1/8 = (5*8 - 1*3)/24 = 37/24 = 1 13/24

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