Question

(а-1)^3-4a(a-1)+3(a-1)(a^2+a+1).мұндағы a=-2

Answer 1

$(a-1)^3-4a(a-1)(a^2+a+1)=\=(a-1)((a-1)^2-4a(a^2+a+1))=\=(a-1)(a^2-2a+1-4a^3-4a^2-4a)=\=(a-1)(1-4a^3-3a^2-6a)\\a=-2\(-2-1)(1-4(-2)^3-3(-2)^2-6(-2))=\=-3(1+32-12+12)=-3*33=-99$