Question

как решить f (x) = х2 + 2х – 3, где f (x) = 0, т. е. х2 + 2х – 3 = 0.

Answer 1

x^2+2x-3 = 0

D = 4-4*(-3) = 16

x1 = (-2+4)/2 = 1

x2 = (-2-4)/2 = -3

Answer 2

равно 0

Answer 3

там есть ответ

Answer 4

Д = 22 – 4 * (- 3) = 4 = 12 = 16.