Question

решите уравнение (x-3)^2+(3-x)(x+3)=(x+2)^2-x^2

Answer 1

$(x-3)^2+(3-x)(x+3)=(x+2)^2-x^2\ x^2-6x+9+9-x^2=x^2+4x+4-x^2\ -6x+18=4x+4\ -6x-4x=4-18\ -10x=-14\ x=1.4$