Question

Sin(пи на 2+x)- cos(пи + x) +1=0

Answer 1

sin(π/2+x)-cos(π+x)+1=0
cosx+cosx+1=0
2cosx=-1
cosx=-1/2
x=+-(π-π/3)+2πn, n∈Z
x=+-2π/3+2πn, n∈Z