Question

2sin x= -корень из 3

Answer 1

2sinx = - √3
sinx = -√3/2
x =  (-1)^(n)(-√3/2) + πn, n∈Z
x =  (-1)^(n+1)(√3/2) + πn, n∈Z
x =  (-1)^(n+1)(π/3) + πn, n∈Z