Question

1/sin^2x+3/sinx+2=0 на отрезке [-7п/2;-2п]

Answer 1

1/sin^2x+3/sinx+2=0 |*sin^2x
1+3sinx+2sin^2x=0
t=sinx
2t^2+3t+1=0
t=-1,-1/2
sinx=-1
x=-pi/2+2pik
sinx=-1/2
x=-pi/6+2pik

Answer 2

-5pi/2

Answer 3

Спасибо