Question

разложите на множители (3x+5)³-216

Answer 1

(3х+5-6)((3х+5)^2+6*(3х+5)+36)=(3х-1)(9х^2+30х+25+18х+30+36)=(3х-1)(9х^2+48х+91)

Answer 2

$((3x+5)-6)((3x+5) ^{2} +6(3x+5)+36)=$
$= (3x-1)(9x ^{2} +30x+25+18x+30+36)= (3x-1)(9x ^{2} +48x+91)$