Question

пожалуйста срочно надо

Answer 1

$\frac{m ^{5} +m ^{4}+m ^{3} }{m ^{3}+m ^{2} } * \frac{m ^{5} +m ^{4}}{m ^{4} +m ^{3}+m ^{2} }= \frac{m(m ^{4} +m ^{3}+m ^{2})}{(m ^{3}+m ^{2})} * \frac{m ^{2} (m ^{3}+m ^{2})}{(m ^{4} +m ^{3}+m ^{2})} =m ^{3}$

$\frac{a-a ^{3} }{a ^{6}+a ^{2} } : \frac{a ^{5}-a }{a ^{5}+a}= \frac{a(1-a ^{2})}{a(a ^{5}+a)} * \frac{a ^{5}+a}{a(a ^{4}-1)} = \frac{(1-a ^{2})}{a(a ^{2}+1)(a ^{2} -1) } =$
=$\frac{-(a ^{2}-1)}{a(a ^{2}+1)(a ^{2} -1) } =- \frac{1}{a(a ^{2}+1)} =- \frac{1}{a ^{3}+a}$

Answer 2

m^5+m^4+m^3/m^3+m^2 * m^5+m^4/m^4+m^3+m^2= m^3(m^2+m+1)/m^2(m+1) *m^4 (m+1)/m^2(m^2+m+1)= m^7(m^3+m^2+m^2+m+m+1)/m^4(m^3+m^2+m+m^2+m+1)=m^7(m^3+2m^2+2m+1)/m^4(m^3+2m^2+2m+1)(всё,что в скобках, сокращается)= m^7/m^4=m^3

a-a^3/a^6+a^2 : a^5-a/a^5+a= a-a^3/a^6+a^2* a^5+a/a^5-a=a(1-a^2)/a^2(a^4+1)*a(a^4+1)/a(a^4-1)=-(1-a^2)/a *(a^2-1)(a^2+1)=(a^2-1)/a*(a^2-1)(a^2+1)= -1/a(a^2+1)