Question

2 под корнем х+3=-х

Answer 1

$2 \sqrt{x+3}=-x \\ (2 \sqrt{x+3)}^2=(-x)^2 \\ 4(x+3)=x^2 \\ -x^2+4x+12=0 \\ D=b^2-4ac=4^2-4*(-1)*12=64 \\ x_1= \frac{-b- \sqrt{D}}{2a}= \frac{-4-8}{-2}=6 \\ x_2= \frac{-b+ \sqrt{D}}{2a}= \frac{-4+8}{-2}=-2$