Question

125^2/3 - 0.25
17 16^1/4- (1/5)^-1 как решеть

Answer 1

$125^{ \frac{2}{3} }-0.25= (\sqrt[3]{125})^{2}-0.25 = 5^{2} -0.25=24.75$
$17* 16^{ \frac{1}{4} }-( \frac{1}{5})^{-1}= 17* \sqrt[4]{16} - \frac{1}{ \frac{1}{5} ^{1} }=17*2-5=29$

Answer 2

$(125)^{ \frac{2}{3} } -0.25= ( \sqrt[3]{125}) ^{2} -0.25= \\ \\ 5^{2} -0.25=25-0.25=24.75$

2.$17*16^{ \frac{1}{4} } - (\frac{1}{5} )^{-1} = \\ \\ 17*\sqrt[4]{16} -5=17*2-5= \\ \\ 34-5=29$