Question

$\sqrt{2x^{2}+3x+4 }=2x+1$

Answer 1

решение смотри на фотографии

Answer 2

$\sqrt{2x^2+3x+4} = 2x+1$
$2x^2+3x+4 = 4x^2+4x+1$
$2x^2+x-3=0$
D=b²-4ac=1-4*2*(-3)=1+24=$\sqrt{25}$=5

x₁=$\frac{-1+5}{4} = \frac{4}{4} =1$

x₂=$\frac{-1-5}{4} = - \frac{6}{4} =-1,5$ - пост. корень