Question

lim x стремится к 4 ((x^2+3x+1)/(x+2))

Answer 1

(x^2+3x+1)/(x+2)=(4^2+3*4+1)/(4+2)=(16+12+1)/6=29/6

Answer 2

$\lim_{x \to 4} \frac{ x^{2} +3x+1}{x+2} = \frac{ 4^{2} +3*4+1}{4+2} = \frac{29}{6} =4 \frac{5}{6}$=4,8(3)≈4,83333333...