Question

$log _{3} ^{2} 3 \sqrt{6} -log _{3} ^{2} \sqrt{6} \\ log _{3}18$

Answer 1

(log(3)3√6-log(3)√6)(log(3)3√6+log(3)√6)/log(318=
=log(3)(3√6/√6)*log(3)(3√6*√6)/log(3)18=log(3)3*log(3)18/log(3)18=1

Answer 2

$\frac{ log^2_{3} 3\sqrt{6} - log^2_{3} \sqrt{6} }{ log_{3} 18} =\frac{ (log_{3} 3\sqrt{6} - log_{3} \sqrt{6})( log_{3} 3 \sqrt{6} + log_{3} \sqrt{6}) }{ log_{3} 18) }=$
$\frac{ log_{3} 3* log_{3}18 }{ log_{3} 18} =1$